00:01
So in this problem we need to find points on this curve where distance from the origin is maximum window.
00:06
There is a correction in the question.
00:08
It should be eight, then only option will match.
00:12
So i will solve this question with the help of parameter coordinate.
00:17
So i will consider these points as r comma theta.
00:25
So r is distance from the origin to the point on the curve.
00:31
So i will replace x as r cost theta and y as r sine theta.
00:41
So if we put these value, we will get 5, 5 r square plus square theta minus 8 times of r square sine theta plus theta plus theta plus theta plus 5 r square sine square theta which equals to 4.
01:04
So if we see this and this will give us 5r square and i will take r square common.
01:12
So r square in bracket 5 minus this can return as 8 sine theta cost theta can return as 4 sine 2 theta equals to 4.
01:26
So from here r square is nothing but 4 upon 5 minus 4 sine 2 theta.
01:36
Need to think for the maximum or minimum value.
01:41
So sine 2 theta is 1.
01:47
If sine 2 theta is 1, so r square would be 4 upon 5 minus 4 and this could be simply we can say that this could be maximum value and that is nothing but simply 4...