Question
The population of a Seattle suburb is growing at a rate of $3.2 \%$ per year. If 30,000 people lived in the suburb in 2008 , determine how many people will live in the town in 2015. Use $y=y_{0} e^{0.032 t}$
Step 1
The initial population $y_{0}$ is 30,000 people. The growth rate is 3.2%, which is equivalent to 0.032 in decimal form. The time $t$ is the number of years from 2008 to 2015, which is 7 years. Show more…
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