The position of a particle of mass $2.17$ kg traveling in a straight line is given by
$$
x=\left(0.179 \mathrm{~m} / \mathrm{s}^{4}\right) t^{4}-\left(2.08 \mathrm{~m} / \mathrm{s}^{2}\right) t^{2}+17.1 \mathrm{~m}
$$
Find the $(a)$ velocity, $(b)$ acceleration, and $(c)$ force on the particle at time $t=7.18 \mathrm{~s}$