Question
The position of centre of mass of a system consisting of two particles of masses $m_{1}$ and $m_{2}$ separated by a distance $L$ apart, from $m_{1}$ will be(a) $\frac{m_{1} L}{m_{1}+m_{2}}$(b) $\frac{m_{2} L}{m_{1}+m_{2}}$(c) $\frac{m_{2}}{m_{1}} L$(d) $\frac{L}{2}$
Step 1
We have two particles, $m_{1}$ and $m_{2}$, separated by a distance $L$. We can consider $m_{1}$ to be at the origin of our coordinate system, so its position is $(0,0,0)$. The position of $m_{2}$ is then $(L,0,0)$. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The centre of mass of a system of two particles of masses $m_{1}$ and $m_{2}$ is at a distance $d_{1}$ from $m_{1}$ and at a distance $d_{2}$ from mass $m_{2}$ such that (a) $\frac{d_{1}}{d_{2}}=\frac{m_{2}}{m_{1}}$ (b) $\frac{d_{1}}{d_{2}}=\frac{m_{1}}{m_{2}}$ (c) $\frac{d_{1}}{d_{2}}=\frac{m_{1}}{m_{1}+m_{2}}$ (d) $\frac{d_{1}}{d_{2}}=\frac{m_{2}}{m_{1}+m_{2}}$
Consider a two-particle system with the particles having masses $\mathrm{M}_{1}$, and $\mathrm{M}_{2}$. If the first particle is pushed towards the centre of mass through a distance $d$, by what distance should the second particle be moved so as to keep the centre of mass at the same position? $\{\mathrm{A}\}\left[\left(\mathrm{M}_{1} \mathrm{~d}\right) /\left(\mathrm{M}_{1}+\mathrm{M}_{2}\right)\right]$ $\{\mathrm{B}\}\left[\left(\mathrm{M}_{2} \mathrm{~d}\right) /\left(\mathrm{M}_{1}+\mathrm{M}_{2}\right)\right]$ $\{\mathrm{C}\}\left[\left(\mathrm{M}_{1} \mathrm{~d}\right) /\left(\mathrm{M}_{2}\right)\right]$ $\{\mathrm{D}\}\left[\left(\mathrm{M}_{2} \mathrm{~d}\right) /\left(\mathrm{M}_{1}\right)\right]$
Position of two particles are given by $x_{1}=2 t$ and $x_{2}=2+3 t .$ The velocity of centre of mass at $t=2 \mathrm{~s}$ is $2 \mathrm{~m} / \mathrm{s}$. Velocity of centre of mass at $t=4 \mathrm{~s}$ will be (A) $2 \mathrm{~m} / \mathrm{s}$ (B) $4 \mathrm{~m} / \mathrm{s}$ (C) $1 \mathrm{~m} / \mathrm{s}$ (D) Zero
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD