00:01
Okay, we're given a position vector, and the first thing that we are going to do is we're going to find its velocity vector.
00:10
So in order to do that, we'll take the derivative of our position vector.
00:16
So to take the derivative, we take the derivative of each individual piece.
00:20
So the derivative of 3t is 3.
00:24
So there's 3 in the i direction, and then plus the derivative of t minus 1 is just 1j.
00:33
So we know our speed without actually even finding a time to put in.
00:39
Normally, you would still have t's in your velocity, but both were linear.
00:44
So we took our 3 squared plus our 1 squared and we get 10 and then we take the square root of 10.
00:51
So the speed is the square root of 10.
00:54
Now, acceleration will be the derivative of velocity, but each of the components are a actual you know, it's just a value.
01:03
There's no more variables left, and so our acceleration is zero in both directions.
01:10
Now, normally, you would need to have already done this piece, but what we need to do is we need to set, you know, the point is given in terms of x and y.
01:21
Well, our x piece is 3t.
01:24
So if you put 3t equal to 3, you can find out what time that happens.
01:28
It happens at time equals 1...