00:01
Here in order to find the force at the equilibrium position, we're going to say that here for part a, r would be equal to the equilibrium position r sub eq.
00:10
And so we can say that the force would simply be equal to the derivative of the potential energy with respect to that equilibrium position evaluated at r equaling r sub equilibrium.
00:25
And so we're going to set this equal to zero to find that equilibrium position.
00:30
And essentially this becomes negative 12a divided by the equilibrium position to the 13th power and this would be plus 6b divided by the equilibrium position to the 7th power we're going to set this equal to 0 and so the equilibrium position would be equal to 2a over b to the one -sixth power.
01:06
And this is simply equalling approximately 1 .122 multiplied by a over b quantity to the one -sixth power.
01:21
So this would be your answer for part a, the formula essentially for that equilibrium position.
01:27
For part b, if rather this defines a minimum in the potential energy curve.
01:37
So part a, and this is, you could simply graph it using a graphing calculator.
01:53
So graph the original function, by graphing the original function a over r to the 12 power minus b over r to the 6th power...