00:01
So for this question we're looking at the decay of plutonium 23a in a pacemaker.
00:08
So it's actually used as a source of power for a pacemaker via its alpha decay.
00:18
And we are looking at what is the percentage decrease in activity, right, after a certain period of time.
00:27
This time you're given is 10 years.
00:30
So we know that the activity at any given point time t is equal to the original amount activity times half to the power of t over the half life and the fraction, right, we can find the fraction of activity left is equals to half to power t over t half.
01:01
And if we were to look at 10 years, right, there will be half, the power of 10 over 86.
01:10
Right, we're given that the t half is 86.
01:14
So we can put that into our calculator, there will be 0 .92.
01:23
So this is the fraction of activity that is left.
01:28
Right? and in terms of percentage, this is actually 92%.
01:31
So 92 % of the original activity is left after 10 years.
01:37
And we want to find out what is the percentage decrease.
01:40
So the percentage decrease, we simply take total of 100 % subtracted by this.
01:47
92 gets 8%.
01:51
So the decrease is 8%.
01:55
Now next, we're looking at what is the power output.
01:59
Right? at power output initially, which is p0, b at zero time.
02:06
And then we want to look at what is p at 10 years.
02:11
So the power, we are assuming it is 100 % from the energy of the alpha particle.
02:20
So the power is essentially the activity, right, the number of decay times the energy of the alpha particle...