00:01
So for part a, we're going to use the relationship m sub 2 cubed divided by the sum of m sub 1 and m sub 2 quantity squared.
00:11
This is going to be equal to v cubed times t divided by 2 pi times the gravitational constant g.
00:20
We know that m sub 1 is equal in 0 .94 times, 0 .9 times the mass of the sun.
00:31
And we know that velocity is 70 meters per second.
00:36
We know the period t is 1 ,500 days.
00:42
Or we could say approximately 1 .3 times 10 to the 8 seconds.
00:49
And so we find that m sub 2 cubed divided by 0 .9 times the mass of the sun plus m sub 2, quantity squared.
01:00
This is going to be equal to 1 .06 times 10 to the 23rd kilograms and knowing that the mass of the sun is approximately equal to 2 .0 times 10 to the 30th my apologies kilograms we can find that after algebraically manipulating or using your solve function in your ti 84 85 or 89 sub 2 would be equal to 7 .0 times 10 to the 27th kilograms.
01:40
We know the, by dividing by the mass of jupiter, rather, we can say that m sub 2 would be approximately equal to 3 .7 times the mass of jupiter.
01:54
This would be our final answer for part a...