00:01
Hello everyone, let us see the following question.
00:03
The presence of arisenic in a sample that may also contain another group 5 element, antimony.
00:09
So, they can be confirmed by first precipitating arisenic 3 plus with antimony.
00:14
So, arisenic is given as aas 3 plus ion.
00:18
It will be having an impurity of antimony 3 plus.
00:21
So, there will be precipitation of anti -aric sulfide, that is a yellow solid.
00:28
So, erysenic sulfide, as2, s3, which is a yellow ppt.
00:37
However, antimony sb2 s3 is a orange color, somewhat it is orange color solid.
00:48
Okay, now leaving, now if fql is added, only antimony dissolves.
00:55
This can be dissolved with the hcl.
00:56
However, this cannot be dissolved.
01:00
It leaves behind as a residue.
01:02
This is even with hcl, it is a yellow residue, loppt.
01:06
Now, the eryssinic sulfide can be then dissolved using equest nitric acid.
01:12
The equation given here as as2s3, okay, with nitric acid, that is hno3.
01:22
In the presence of water, that is h2o, it forms arisenate.
01:32
And no and sulfur.
01:38
So, this is also given that this is solid, this is acquiesce, this is liquid, this is equious, no is a gas, sulfur is a solid, so this is precipitative.
01:57
So we can also balance the equation as this is 3, this is 10 sulfuric acid, water is 4 unit, ericinate is 1, 6 unit, nitrogen monoxide is 10 unit, sulfur 9.
02:13
This is given already in the question.
02:15
Now, based on this, there is a question.
02:19
Finally, the presence of arisenic is confirmed by adding agno3 to the solution of h3aso4.
02:26
H3 aso4 to this we have to add a solution of ag no3.
02:34
So, we get the precipitate of something called agx, as1 unit and oxygen y.
02:47
So, the composition of this solid is so that in this, there is ag and ericinate the percentage is given.
02:57
Percentage of ag is given as 69 .964 percentage.
03:04
Eracinate is given as 16 .199 percentage.
03:10
Similarly, the remaining percentage should be oxygen, that is 13 .837.
03:18
Now we have to find out the formula of this particular compound.
03:21
So, it's given as only x, y...