Question
The Pressure and density of a diatomic gas $\gamma=(7 / 5)$ Change adiabatically from $(\mathrm{P}, \mathrm{d})$ to $\left(\mathrm{P}^{1}, \mathrm{~d}^{1}\right)$ If $\left(\mathrm{d}^{\prime} / \mathrm{d}\right)=32$then $\left(p^{\prime} / p\right)$ Should be(A) 128(B) $\{1 /(128)\}$(C) 32(D) None of this
Step 1
Step 1: We know that for an adiabatic process, $PV^{\gamma} = \text{constant}$, where $P$ is the pressure, $V$ is the volume, and $\gamma$ is the heat capacity ratio. Show more…
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The pressure and density of a diatomic gas $(\gamma=7 / 5)$ change adiabatically from $(p, d)$ to $\left(p^{\prime}, d^{\prime}\right)$ if $\frac{d^{\prime}}{d}=32$, then $\frac{p^{\prime}}{p}$ should be (a) $1 / 128$ (b) 32 (c) 128 (d) None of these
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Round 2
The pressure and density of a diatomic gas (gamma= 7 / 5) change adiabatically from (P, d) to (P', d'). If d '/d=32 , then P' /Pshould be (a) 1/128 (b) 32 (c) 128 (d) None of the above
The pressure $P_{1}$ and density $d_{1}$ of a diatomic gas $(\gamma=7 / 5)$ change to $P_{2}$ and $d_{2}$ during an adiabatic operation. If $\frac{d_{2}}{d_{1}}=32$, then $\frac{P_{2}}{P_{1}}$ is (a) 76 (b) 128 (c) 168 (d) 298
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