Question
The pressure, $p$, on an object under a fluid of density $\rho$ (Greek letter rho) is given by$$\frac{\mathrm{d} p}{\mathrm{~d} z}=-\rho g$$where $z$ represents depth and $g$ is the acceleration due to gravity. Find an expression for $p$.
Step 1
So, we have: $$ \int \frac{\mathrm{d} p}{\mathrm{~d} z} \mathrm{d}z = -\rho g \int \mathrm{d}z $$ Show more…
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