We want to show that $(1-p)^N \rightarrow e^{-Np}$.
We can rewrite $(1-p)^N$ as $e^{\ln((1-p)^N)}$. Using the property of logarithms, this becomes $e^{N\ln(1-p)}$. Now, we can substitute the given result into this expression: $e^{N(-p)} = e^{-Np}$. Thus, we have
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