Question
The product obtained by reaction of PhCHO and $\mathrm{MeCHO}$ are
Step 1
This results in the formation of a carbanion. \[ \begin{array}{c} \mathrm{PhCHO} + \mathrm{MeCHO} \xrightarrow[\text{base}]{\text{}} \mathrm{PhCHO} + \mathrm{CH_{2}^{-}CHO} \end{array} \] Show more…
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