The product of inertia for an area about inclined axes is given by the formula
$$
I_{u v}=I_x \sin \theta \cos \theta-I_y \sin \theta \cos \theta+I_{x y}\left(\cos ^2 \theta-\sin ^2 \theta\right)
$$
Show that this is equivalent to
$$
I_{u v}=\frac{I_x-I_y}{2} \sin (2 \theta)+I_{x y} \cos (2 \theta)
$$