00:01
Okay, in this question, the project rate of increase in enrollment at a new college is estimated by de over dt equals to 5 ,000 t plus 1 raised to the power minus 3 by 2 for the time period greater than equals to 0, where it is the project enrollment in t years.
00:23
So we have to find the project enrollment, okay, for the first for the t years.
00:29
So, we have to find e here, okay, e t, and that is the integration of de, okay? so the de is 5 ,000 t plus 1 raised to the power minus 3 by 2, okay, dt, and the integration of de that we call et, it will be integration 5 ,000, t plus 1, raise to the power minus 3 by 2.
00:59
D t or we can say et is 5 ,000 okay and integration of t plus one raised to the power minus 3 by 2 it will be t plus 1 raise to the power n plus 1 that minus 3 by 2 plus 1 it will be minus 1 by 2 divided by minus 1 by 2 or we can say multiply minus 2 okay and plus c or we can say et will be minus 2 .5 ,000 it will be minus 10 ,000, okay, t plus 1, t plus 1 raised to the power minus half plus c okay and now as per the question at the starting point that is t equals to 0 then enrollment is 2000 or we can say when t equals to zero the value of e is 2000 so we will put these value into this equation and e is 2 ,000 equals to minus 10 ,000, okay, and t is zero, so zero plus one raised to the power minus half, so it will be one plus c...