The propane fuel (C3H8) used in gas barbeques burns...

Name: Problem 57, Chapter 9: Chemistry: Structure and Properties
Uploaded: 2021-08-26T01:10:56-08:00
Duration: 4 min 12 s
Channel: Christopher Nilsen
Description: The propane fuel (C3H8) used in gas barbeques burns according to a thermochemical equation: If a pork roast must absorb 1.6 * 103 kJ to fully cook, and if only 10% of the heat produced by the barbeque is actually absorbed by the roast, what mass of CO2 is emitted into the atmosphere during the grilling of the pork roast?

The propane fuel (C3H8) used in gas barbeques burns according to a thermochemical equation: If a pork roast must absorb 1.6 * 103 kJ to fully cook, and if only 10% of the heat produced by the barbeque is actually absorbed by the roast, what mass of CO2 is emitted into the atmosphere during the grilling of the pork roast?

The propane fuel (C3H8) used in gas barbeques burns according to a thermochemical equation:

If a pork roast must absorb 1.6 * 103 kJ to fully cook, and if only 10% of the heat produced by the barbeque is actually absorbed by the roast, what mass of CO2 is emitted into the atmosphere during the grilling of the pork roast?

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Transcript

00:01 All right, so let's do some barbecue.

00:04 If we take some propane and oxygen, due combustion will create co2 and h2o.

00:11 That will also produce heat.

00:14 It will release 2 ,04 kilojoules of energy.

00:18 And of course, that energy goes into food when we wind up barbecuing.

00:23 But we all know that not all of the energy goes into the food itself.

00:26 We know a lot of it gets wasted.

00:28 We know the barbecue is hot.

00:31 And so not all the heat just goes into the food, but out to the atmosphere as well.

00:38 So if we know that we need 1 .6 times 10 to the 3 kilojoules of energy to cook a substance, but we also know that that's 10 % efficient in terms of our barbecue, that means we really need 10 % times the amount of energy to get to a hundred percent.

01:07 So what that really means is we need 1 .6 times 10 to the 4 kilojoules of energy to barbecue because only 10 percent of it will go into our food and we need 10 percent of 1 .6 times 10 to the fourth or 1 .6 times 10 to the third kilojoules.

01:30 So we're going to use the larger number to figure out how much co2 we will emit.

01:37 So we're going to start out with that amount of heat.

01:45 Now what do we know? okay, we know from our delta h that we wind up using 2 ,04 kilojoules of energy.

02:01 Well, we release that for how much co2...

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