the-propane-fuel-c3h8-used-in-gas-barbeques-burns-according-to-a-thermochemical-equation-if-a-pork-r

Question

The propane fuel (C3H8) used in gas barbeques burns according to a thermochemical equation:

If a pork roast must absorb 1.6 * 103 kJ to fully cook, and if only 10% of the heat produced by the barbeque is actually absorbed by the roast, what mass of CO2 is emitted into the atmosphere during the grilling of the pork roast?

Christopher Nilsen · Accepted Answer

All right, so um let&#x27;s do some barbecue. If we take some propane and oxygen do combustion will create CO. Two and H 20. That will also produce heat. It will release 2044 killing tools of energy. Of course that energy goes into food when we wind up barbecuing. But we all know that not all of the energy goes into the food itself. We know a lot of it gets wasted. We know the barbecue is hot. Um And so not all the heat just goes into the food, but out to the atmosphere as well. So if we know that we need 1.6 times 10 to the three Killah jewels of energy to cook a substance. But we also know that that&#x27;s 10% efficient on Uh in terms of our barbecue, that means we really need 10 times the amount of energy to get to 100%. So what that really means is we need 1.6 times 10 to the four killing tools of energy to barbecue because Only 10% of it will go into our food and we need 10% of 1.6 times 10 to the fourth or 1.6 times 10 to the third killer jewels. So we&#x27;re going to use the larger number to figure out how much CO two we will omit. So we&#x27;re gonna start out with that amount of heat. Yeah. What do we know? Okay, we know from our delta H. That we um wind up using 2044. Kill the jewels of energy. Well we release that for how much co two. If we take a look at the co two, We&#x27;ve got three of them. So we released that amount of energy for three moles of CO two. Now, the other thing before we move on to the last step is this 1.6 times 10 to the fourth. Killing joules of energy. It&#x27;s going into the food but it has to come out of somewhere. It&#x27;s coming out of the reaction and out is negative. Yeah. So later these negatives will wind up canceling out Now to get mass of co two. Now we just go to Mulcair mass one mole of CO two. If we add up a carbon into oxygen is 44 0.1 grams. And now if we cancel out our killer jewels, we cancel out our moles of CO two. We&#x27;re left with grams of CO two. And when we answer this problem, we&#x27;re going to have to answer to two significant figures. Um Because we only have two significant figures in 1.6 times 10 to the fourth killer jewels. And so when we do the math, we wind up with um 1000 3rd 1033g. But we can&#x27;t use 1033 because we&#x27;re only going to two significant figures 1000 g. And if we put a little line over that, that would tell you that second zero is significant. And if you don&#x27;t know the rule about the line, then what you have to do is have your answer in scientific notation. So you have the two significant figures at 1.0 So 1.8 times 10 to the 3rd g is 1000 g. But to our two significant figures.

David Collins · Answer

to determine the mass of carbon dioxide that is released. We first need to know the total amount of heat that is required. If a pork roast requires 1.6 times 10 to the third killer jewels and only 10% of the heat released is absorbed. Then we need 1.6 times 10 to the fourth amount of heat in order to cook the pork roast So that 10% of 1.6 times 10 to the four Gives us the 1.6 times 10 to the third killer jewels that&#x27;s required. We also need a balanced chemical reaction for propane producing the heat and carbon dioxide. Here&#x27;s the balanced chemical reaction showing that three moles of carbon dioxide are produced When one mole of propane burns And 2044 killer jewels of heat are released. So we&#x27;ll take our total amount of energy. As I mentioned, it will be 1.6 times 10 to the four killer jewels, Divided by the amount of heat that is released per three moles of carbon dioxide. Then convert the moles carbon dioxide into grams By multiplying by the molar mass carbon dioxide And we get 1.3 times 10 to the 3g or two. Just two significant figures because that&#x27;s all we have here, We get 1.0 kg of carbon dioxide

Amy Jiang · Answer

so the amount of heat of 38 times are changing. Age of combustion. No, that&#x27;s the number of more A C three. Hey, Hey, you are No, I agree. Hey is equal to you over to change American Western, and that&#x27;s equal to 4560. Kill Jules over 2219 Children. Or were long, which gives me 2.55 Okay, now are more math. The 38 physical to 44.9 grams. So the mass of the P eight, we have 2.55 most of it. Multiply it by the ratio of its more rats. 44.9 grams over more. You&#x27;re in a 90.60 grams of these three.

James Irizarry · Answer

Okay, guys, we&#x27;re doing question number seventy two in chemistry of Central Science, We&#x27;re going to be determining how much heat is released when us when ten grams of C three h eight aid is combusted. Undersander conditions. So the way we have to figure this out is by hey converting the number care of grams into malls. And we have the entropy up there. There were going to be using that because that&#x27;s the amount of energy released Permal. So we had to figure out how many molds we have our substance. Before we can calculate anything, the ten divided by forty four or is going to be approximately zero point two three moles more. So now we get multiplied that at one hundred eight foot, one hundred and three point eight five. Killer Jules per mole Time&#x27;s your point three zero point two three moles. Yeah, five. So that means that that we have two thousand three hundred and eighty eight point five five. Killer Jules. Yes. Now they&#x27;re asking for how much is released. So is released. So they&#x27;re asking for the magnitude of this which is going to be chiu is equal to two thousand three hundred and eighty eight point five five. Killer Jules of our substance of heat is released from burning this fuel.

Rebecca Wallace · Answer

Okay, This problem references 6.3 with the value of combustion of propane. So it wants to know what master propane must be burned to furnish this amount of energy. Assuming the huge transfer process is only 62 set. Except this is the value of heat from 6.3. So if we assume that 60% that means that for every 100 jewels, only 60 actually comes out. Uh, so that really leaves us with 2.2 times 10 to the eighth. Jules, Now we just need to use We need to get from Jules gym mats. So we&#x27;re gonna use this to 0.2 times 10 to the eighth as our starting point because that&#x27;s what we know. We need to point to your times 10 to be ate the jewels. So from the balanced equation, we know that for every mole of the propane can produce 2221 times 10 to the third Jules jewels. Right? Because it gives it in killer Jules, we put in jewels before we actually look through. Then we want to go from moles to mass using Moeller masto. Every mole of propane should weigh 44. What? 09 grams. And then we met through and we end up with 4.4 times, 10 to the third grams of propane.

Ronald Prasad · Answer

Mhm. So Germany entropy of combustion for propane, propane as a chemical formula C three H eight. Gas phase combustion is plus oxygen gas Were produced co two gas. And to a gas to balance this, we need a five here, Three here and for here. So to determine the entropy of combustion here. Yeah. We&#x27;re going to start with carbon solid or to gas. Pretty sick. Co two gas first about the age not Formation here is equal to -394 Villa jewels per mole. Then we&#x27;ll have age too. Yes, Plus 102 gas. And this will produce H20. Gas lT it&#x27;s not formation Is equal to -242. So the jewels per mole. And Then we have c. three J gas. Mhm. Mhm. Which will produce three carbon solid. Mhm. And for each to gas. And this has given to us the question As 104 kg per mole. Mhm. Well Let&#x27;s multiply this by three, 3, 3 and three. We&#x27;ll take this and multiply it by three. Take the second one will multiply it by four. So before for and four fiscal here we multiplied by four. If we combine all this together here, we&#x27;ll see that the four H two S will counsel three carbons will cancel and we left today. C three H eight gas combined, the oxygen&#x27;s at 502 Gas will produce three C 02 gas And four H 20 gas. And if we add up all of our up ph not values the the th the entropy of combustion here works out to minus 2000 and 46 killer jewels promote.

Christopher Nilsen · Answer

All right, so in this question, it&#x27;s all about the conviction of propane. Thio come on side of water and down to hate for the reactions minus two. So the question is telling us that whole clothes needs six times stands about three villagers and on Lee, then the saints on the hates. Nice, brutish from this reaction is actually observed. So But how much of anything? And obviously so what&#x27;s a month off? Energy have produced from this reaction? Well, 10% off its being regulated is thio be 10% much blood. My hex will be forced to wants this time since our three villagers so fine Hex X is going to be. I want 16 That stands powerful killer Jos. Okay, so that&#x27;s just the amount of stout produce from this reaction that 10% off it will be equals two. What&#x27;s this nonsense about 32 jobs. Now we get to completely cook a pork roast. Okay, Now, one more off the propane. Well, you sound true. Therefore, fall killed Jules beads. Therefore won&#x27;t want six them stands for four kilometers. Maybe he couldn&#x27;t you How many more can call? That&#x27;s why it was so for? Why my cross multiplying? Why be more times? Won&#x27;t one city excessiveness ruffle kill Jews by buying trip for all ages? And why would be some point it to eight more off us? Three ages? So that is the number of more off our C three h. It&#x27;s that need to be Columbo State toe produce the same amount of energy there will need to constantly cook a focus. What a question wants us to calculate their masks off c 02 There will be produced from the conviction off that amount off. Okay, so we know that someone&#x27;s hits to hit more love Seat three agents was produced. Why that would be needed. But from the question one more off the seat doing agent with previous three mole sauce. You too talking, going and say that Warm Also between J. JJ produced three more students to the Air Force ones. Uh, something It&#x27;s you. It&#x27;s mostly 3 88 with produce some point, a two way street more. Stewart&#x27;s on now be wants to 23 points for three years, so we know that a number of more is master five. I&#x27;m on the most, and I&#x27;m all Exchange E 3.483 Then last Denby was, too. What&#x27;s a full grounds from hole? That&#x27;s the last. Move the muscles here, too. Yeah, For the mast, there will be a big blow. Darts off 23.483 more than 44 grounds for more. So don&#x27;t be 133.27 wraps. And, uh, that&#x27;ll be Won&#x27;t want Theo. Three kilograms. I&#x27;ll see you two said. I&#x27;ll be the 1.3, grandma. See you too. Well, birthdays, fun mystery action.

Christopher Nilsen · Answer

continuing on with our work surrounding thermodynamics in this podcast, we&#x27;re gonna be taking a look at the entropy of reaction. This has the relationship with a stogie, a commentary of the chemical reaction. So, for example, when we multiply our reaction by a factor of Delta H reaction, this is also multiplied by a similar factor. And so the sign of Delta H reaction is reversed if we are to in fact reverse that chemical reaction. So we have our balanced equation. So we&#x27;ve got three C three h eight, but propane add five to up, and we have our possible r 03 co two at four h two. Well, obviously we&#x27;ve got our respective states. But just to save time, I won&#x27;t draw them on because that&#x27;s not the focus of this podcast. So we have the heat released during the both reaction. That is 2.4 four times 10 to the 3 kg joules. So we have three moles of co two that is released drawing off production off heat eso we have 10% off 2.44 times 10 to 3 killer jewels. That is 2.44 times 10 2 kg jewels and so therefore, this amount of heat is absorbed during the grilling off three miles of CO. Two. So in order to fully cook this pork, the amount of heat that is needed is 1.6 times 10 to the 3 kg jewels. We have the moles of CO two emitted that is 1.6 times center. Three kill Jews multiplied by three miles Co. To divide that by 2.44 times 10 to the to kino jewels that we just looked at. The value we get then is 23.48 moles off CEO too. So therefore, the massive co two emitted during the grilling. Off this pork, we have 23.48 miles of CO two multiplied by that by 44 grands. Bye bye. One month What we get is 1.0 kg on C 02 So 1 kg of co two is emitted into the atmosphere In this process,

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Charcoal is primarily carbon. Determine the mass …

Problem 57 Medium Difficulty

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$1.0 \mathrm{~kg}$

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