Question
The proton NMR spectrum is shown for a compound with formula $\mathrm{C}_6 \mathrm{H}_8 \mathrm{Cl}_2 \mathrm{O}_2$. The two chlorine atoms are attached to the same carbon atom. The infrared spectrum displays a strong band $1739 \mathrm{~cm}^{-1}$. The normal carbon-13 and the DEPT experimental results are tabulated. Draw the structure of this compound.$$\begin{array}{ccc}\hline \text { Normal Carbon } & \text { DEPT-135 } & \text { DEPT-90 } \\\hline 18 \mathrm{ppm} & \text { Positive } & \text { No peak } \\31 & \text { Negative } & \text { No peak } \\35 & \text { No peak } & \text { No peak } \\53 & \text { Positive } & \text { No peak } \\63 & \text { No peak } & \text { No peak } \\170 & \text { No peak } & \text { No peak }\end{array}$$
Step 1
This indicates that the compound contains 6 carbon atoms, 8 hydrogen atoms, 2 chlorine atoms, and 2 oxygen atoms. Show more…
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