00:02
In this problem, we have an amount of oxygen that can dissolve in water, which is dependent on the water's temperature.
00:10
So in this case, if we look at a graph, here we have the solubility of oxygen.
00:15
So i'm just going to call it s and the temperature t.
00:19
Our graph looks something like this, which means that as the temperature is increasing, the amount of oxygen that is able to be dissolved is decreasing.
00:28
So we have an inverse relationship.
00:30
This kind of reminds me of baking.
00:32
I love to bake.
00:34
And when you are dissolving yeast into water, the higher the temperature of the water, the lower amount of yeast is dissolved because it actually kills the yeast.
00:44
So it's kind of a similar relationship.
00:46
So here we're going to let s represent the solubility of the oxygen.
00:50
So let me just write that out.
00:51
So s is going to be the solubility, which just means the amount of oxygen that's able to be dissolved.
01:06
And those units are in milligrams per liter.
01:10
And we know that based off of the graph.
01:13
And then we're going to say that t is going to be the temperature of the water.
01:18
So i'm just going to write temp of water.
01:22
And the temperature of the water is in degrees celsius.
01:26
And again, we get that from the graph.
01:28
So in part a, they want us to figure out what s prime of t is.
01:34
And interpret that.
01:35
So s prime of t, well, that's just the derivative.
01:39
So s prime of, oops, t.
01:43
So that is the derivative.
01:45
And when we think about derivatives, we need to remember that a derivative is a rate of change.
01:49
So anytime that we're talking about derivatives and trying to explain what a derivative is, we should be using the word rate or rate of change.
01:58
Something, they go hand in hand, so something like that.
02:01
So in this case, it would be the rate at which, well, in general, the rate of change is the rate at which one quantity changes with respect to another.
02:12
So here we have two variables, right? we have s and we have t.
02:15
So s is our solubility of oxygen, and t at the temperature, is what it's in respect to.
02:25
So if we wanted to write this out as an actual answer, we can say that s prime of t is the rate.
02:36
At which the solubility of oxygen changes.
02:59
So there we have rate of change.
03:03
Those words are in there already.
03:05
Changes with respect to the temperature of the water.
03:32
And that if we want to say that that's our t, we could say you know, put s up here just so you know we're clear in our answer.
03:41
So s prime of t is the rate at which the solubility of oxygen changes with respect to the temperature of the water.
03:48
And again, those key words that we have rate of change.
03:52
Here we have the rate, oops, of change.
03:56
So we're still using that idea.
03:58
Then we have to figure out the units for this...