The quantum yield for formation of 3-methylcyclobutene from $E-1,3-$ pentadiene by $254 \mathrm{~nm}$ radiation is ten times greater than for cyclization of the $Z$-isomer. 1,3-Dimethylcyclopropene is also formed but the difference in $\Phi$ for this reactions is only a factor of two. Offer an explanation for these differences in terms of energy surfaces that are involved.