The quinhydrone half cell is represented as $\mathrm{Pt} / \mathrm{H}_2 \mathrm{Q}, \mathrm{Q}$, $\mathrm{H}^{+}(\mathrm{aq})$.
$\mathrm{H}_2 \mathrm{Q}$ and Q are present in $1: 1$ molar ratio. The electrode potential of the above electrode is written as
(a) $\mathrm{E}=\mathrm{E}^{\circ}+0.059 \log \left[\mathrm{H}^{\prime}\right]$
(b) $\mathrm{E}=\mathrm{E}^{\bullet}-0.059 \log \left[\mathrm{H}^{-}\right]$
(c) $\mathrm{E}=\mathrm{E}^{\circ}-\frac{0.059}{2} \log \left(\frac{\mathrm{H}_2 \mathrm{Q}}{\mathrm{Q}}\right)$
(d) $\mathrm{E}=\mathrm{E} 0+\frac{0.059}{2} \log \left(\frac{[\mathrm{Q}]\left[\mathrm{H}^{+}\right]}{\left[\mathrm{H}_2 \mathrm{Q}\right]}\right)$