00:01
Not being artist, this was a tough, an artist, this was a tough diagram.
00:06
So go ahead and look at problem 2, 247.
00:12
So you can see a better problem here.
00:14
Well, let's take a look at the problem.
00:16
The radar tracking antenna oscillates around its vertical axis according to theta equals, theta initial times a cosine of the circular constant.
00:29
The constant circular frequency and t.
00:33
And 2 theta initial is a double amplitude.
00:36
Of oscillation.
00:38
Simultaneously, the angle elevation at this, hang on a moment, having a little memory issue.
00:58
I just need to see, i think it's phi.
01:05
Yeah, okay, so that's going to be phi.
01:12
This increase in the constant rate of phi equals k.
01:16
Determine the expression for the magnitude a of the acceleration of the signal horn as it passes position a and it passes the top of position b, assuming that theta equals zero at that instant.
01:31
Okay, let's see if there's any chance i can figure this out.
01:42
Okay, so the position vector in a cartesian coordinate system, okay, there'll be a lot of writing on this one.
02:28
Okay, so r, b, okay, and then derive time to derive over time two times.
03:15
Okay.
03:50
And then negative.
04:20
Okay, i think i got all that.
04:22
I just want to verify i've got it.
04:25
Got too many of these here.
04:30
And this should be cosine.
04:33
I always have to check these because it gets really easy for me to change these.
04:36
There we go.
04:39
And then using equals zero.
04:45
We'll get the following.
04:47
Are you ready? can't put that one on there.
05:35
So i'm going to go to my next line.
05:37
Minus, start my minus over here.
06:04
Okay, and then my a -y, see if i can write a smidge smaller's here.
06:35
I can't really...