Question
The radius of the second Bohr orbit, in terms of the Bohr radius, $a_{0}$, in $\mathrm{Li}^{2+}$ is:(a) $\frac{2 a_{0}}{3}$(b) $\frac{4 a_{0}}{9}$(c) $\frac{4 a_{0}}{3}$(d) $\frac{2 a_{0}}{9}$
Step 1
Step 1: The formula for the radius of the nth Bohr orbit is given by $r_{n} = \frac{n^{2}a_{0}}{Z}$, where $n$ is the principal quantum number, $a_{0}$ is the Bohr radius, and $Z$ is the atomic number. Show more…
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The radius of the second Bohr orbit, in terms of the Bohr radius, $a_{0}$, in $\mathrm{Li}^{2+}$ is: (a) $\frac{2 a_{0}}{3}$ (b) $\frac{4 a_{0}}{9}$ (c) $\frac{4 a_{0}}{3}$ (d) $\frac{2 a_{0}}{9}$
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