The rate constant for the reaction, $2 \mathrm{~N}_{2} \mathrm{O}_{5} \rightarrow 4 \mathrm{NO}_{2}+\mathrm{O}_{2}$
is $3.0 \times 10^{-4} \mathrm{~s}^{-1}$. If start made with $1.0 \mathrm{~mol} \mathrm{~L}^{-1}$ of $\mathrm{N}_{2} \mathrm{O}_{5}$, calculate the rate of formation of $\mathrm{NO}_{2}$ at the moment of the reaction when concentration of $\mathrm{O}_{2}$ is $0.1 \mathrm{~mol} \mathrm{~L}^{-1}$.
a. $1.2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$
b. $3.6 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$
c. $9.6 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$
d. $4.8 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$