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The rate constant for the second-order reaction$$2 \mathrm{NO}_{2}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g)$$is $0.54 / M \cdot$ s at $300^{\circ} \mathrm{C}$. How long (in seconds) would it take for the concentration of $\mathrm{NO}_{2}$ to decrease from 0.62 $M$ to 0.28 $M ?$

$$3.6 \mathrm{s}$$

Chemistry 102

Chapter 6

Chemical Kinetics

Kinetics

Drexel University

Brown University

Lectures

22:42

In probability theory, the conditional probability of an event A given that another event B has occurred is defined as the probability of A given B, written as P(A|B). It is a function of the probability of B, the probability of A given B, and the probability of B.

04:55

In chemistry, kinetics is the study of the rates of chemical reactions. The rate of a reaction is the change in concentration of a reactant over time. The rate of reaction is dependent on the concentration of the reactants, temperature, and the activation energy of the reaction.

01:25

The rate constant for the …

03:18

02:34

The first order reaction,<…

02:07

Hello. So today we're going to be looking at this reaction right here. So this is a second order reaction as we conceive from our rate constant that we've been given. And we know that we're starting off with 0.62 mil Arat, ease off nitrogen dioxide and we want to know what what time will have 0.28 mil? Araji. Well, remember what's unique about a second order reaction? Well, if you plot the inverse of its reacted concentration in this case, nitrogen dioxide over time you'll get a straight line on the slope of this line is the reactant. Our case. Nitrogen dioxide at some time is equal to the rate constant times, time plus one over the initial concentration. And you'll see well, we know what we're starting with. We know what we end up with, and we know the rate constant. All right, What we want is the time. So why don't we just plug in? So let's plug in. You have 1/0 0.28 is equal to 0.54 times time, plus one over 0.62 And so let's do some math. So one divided by 10.62 is 1.6 and we take one divided, right, 2.28 and then some. Track that, then divide by 0.54 and we will see that our answer is three 0.6 seconds. So in 3.6 seconds, we go from 0.62 Miller T 20.28 mil. Araji, There we have it.

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