00:01
Hi guys, let's solve problem 16 .59.
00:05
The rate constant at a certain temperature is given.
00:10
We need to find out the rate constant at 75 degrees celsius.
00:14
So from the arrhenius equation, we know rate is equal to.
00:23
Now we can compare the arhaneous equation at these two conditions.
00:31
K2 by k1 is equal to a exponential.
00:35
Exponential activation energy divided by rt2 divided by a exponential minus ea by rt1.
00:48
So the frequency factors will be gone and we will be left with k2 equal to k1 exponential negative ea by rt2 because this is negative it will go up and it will look positive now, ea divided by r, t1.
01:14
Or we can write k1, exponential, ea divided by r, 1 by t1 minus 1 by t2.
01:27
Now let's insert all the values given.
01:32
K1 is 4 .7 multiplied by 10 inverse 3, second inverse 1, exponential.
01:42
Convert the activation energy from kilojoum to jule, 33 .6 multiplied by 10 cube, jule, mole, inverse 1...