The rate law for the decomposition of $\mathrm{N}_{2} \mathrm{O}_{5}$ is rate $=$ $k\left[\mathrm{~N}_{2} \mathrm{O}_{5}\right] .$ If $k=1.0 \times 10^{-5} \mathrm{~s}^{-1},$ what is the reaction rate when the $\mathrm{N}_{2} \mathrm{O}_{5}$ concentration is $0.0010 \mathrm{~mol} \mathrm{~L}^{-1}$ ?