Question
The rate law for the reaction:$\mathrm{RCl}+\mathrm{NaOH}(\mathrm{aq}) \longrightarrow \mathrm{ROH}+\mathrm{NaCl}$is given by Rate $=k[\mathrm{RCl}]$. The rate of the reaction will be(a) Doubled on doubling the concentration of sodium hydroxide.(b) Halved on reducing the concentration of alkyl halide to one half.(c) Decreased on increasing the temperature of reaction.(d) Unaffected by increasing the temperature of the reaction.
Step 1
(a) The rate law is given by Rate = k[RCl], which means that the rate of the reaction depends only on the concentration of RCl and not on the concentration of NaOH. Show more…
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The rate law for the reaction : $$ \mathrm{RCl}+\mathrm{NaOH} \text { (aq.) } \rightarrow \mathrm{ROH}+\mathrm{NaCl} \quad[1988-1 \text { Mark] } $$ is given by, Rate $=k_{1}[\mathrm{RCl}]$. The rate of the reaction will be (a) doubled on doubling the concentration of sodium hydroxide. (b) halved on reducing the concentration of alkyl halide to one half. (c) increased on increasing the temperature of the reaction. (d) unaffected by increasing the temperature of the reaction.
Chemical Kinetics and Nuclear Chemistry
Topic 1 : Rate of Reactions, Order of Reactions and Half Life Period
The rate law for the reaction $\mathrm{RCl}+\mathrm{NaOH} \rightarrow \mathrm{ROH}+\mathrm{NaCl}$ is given by Rate $=\mathrm{k}(\mathrm{RCl})$. The rate of the reaction is a. Halved by reducing the concentration of $\mathrm{RCl}$ by one half. b. Increased by increasing the temperature of the reaction. c. Remains same by change in temperature. d. Doubled by doubling the concentration of $\mathrm{NaOH}$.
A reaction has the rate law, Rate = k[A]2[B] Which change will cause the greatest increase in the reaction rate? a) decreasing the temperature without changing the concentrations b) doubling the concentration of B c) quadrupling the concentration of B d) tripling the concentration of B e) tripling the concentration of A
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