Question
The ratio of maximum to minimum intensity at a place due to superposition of two waves represented by $y_{1}=3 \sin (200 t) \mathrm{cm}$ and $y_{2}=4 \cos (208 t) \mathrm{cm}$ will be(A) $7: 1$(B) $49: 1$(C) $4: 3$(D) $16: 9$
Step 1
The amplitudes of the two waves are given by the coefficients of the sine and cosine functions. In this case, the amplitudes are 3 cm and 4 cm. Show more…
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The ratio of maximum to minimum intensity at a place due to superposition of two waves represented by y t 1 = 3sin(200 ) cm and y t 2 = 4 cos(208 ) cm will be
If the ratio of amplitude of two waves is 4 : 3, then the ratio of maximum and minimum intensity is (a) 16 : 18 (b) 18 : 16 (c) 49 : 1 (d) 94 : 1
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