00:01
So in this problem, we're told that a molecule of n203 has an o to n ratio of 12 to 7.
00:09
And another nitrous oxide molecule has an o to n ratio of 16 to 7.
00:17
And we want to determine what the formula of this 16 to 7 1 is.
00:21
So what we can do is we can find moles of o and moles of n and then scale those up to whole numbers.
00:30
So the moles of o is going to be 16 divided by 16, since there are 16 grams per mole in oxygen.
00:39
And so that gives us one.
00:40
Now, for nitrogen, we do 7 divided by 14, since there's 14 grams per mole in nitrogen.
00:47
So that gives us 0 .5.
00:49
We multiply these to get whole numbers, 2 to 1...