Question
The ratio of the radii of gyration of a circular disc and a circular ring of the same radii about a tangential axis in the plane is :(a) $1: 2$(b) $\sqrt{5}: \sqrt{6}$(c) $2: 3$(d) $2: 1$
Step 1
Therefore, the moment of inertia of the disc is $I_{disc} = I_{cm} + md^2 = \frac{1}{2}mR^2 + mR^2 = \frac{5}{4}mR^2$. Show more…
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