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Hey guys, so in this question, we're given the reaction between nitrogen monoxide and hydrogen gas, and it's forming nitrogen gas and water.
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We're given that the order with respect to nitrogen monoxide is second order, and we're given that the order with respect to hydrogen gas is first order, given by this rate law right here.
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And we're asked to find a three -step mechanism.
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And we're given the first two steps, which are both fast steps, and these two first steps are according to the information from the textbook.
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And we have to try to find the second step for this three -step mechanism to complete this question.
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So we have to make sure that our order with respect to the rates or the reactants is the same.
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So the first thing i'm going to do is i'm going to make sure that's so.
01:00
For nitrogen or nitrogen monoxide, the order is two.
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So that means that we have to have a coefficient of two in front of that in our reactants and a coefficient of one in front of hydrogen gas.
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So that we'll just write that as h2.
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And we know that this step has to be the slow step.
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And we can say that the coefficients of this are equal to the order because this is the slowest step, and the slowest step we know is the rate determining step.
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So the orders are going to be the same as our molecularity here.
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The next thing i'm going to do is i'm going to look at my intermediates.
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So i have an intermediate of n2ho2, and that doesn't appear in any of the reactants here on steps 2 and 3.
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So i'm going to go ahead and add it to step two.
02:00
And we do this because we want our intermediates to cancel out.
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So we are left with only the reactants and the products given in the overall reaction.
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So i have that here.
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And i'm going to go ahead and do the same thing for my other intermediate...