00:02
In this problem, we have to calculate the activation energy for the reaction.
00:09
2 moles of nocl gives 2 moles of nitric oxide and cl2 gas.
00:22
And in another subpart, we have to calculate rate constant at 435 kelvin.
00:29
Suppose k1 and k2 are rate constant at temperature.
00:54
T1 and t2 respectively.
01:05
Here, k1 equals to 9 .3 into 10 x to the power minus 6 per second and t1 equals to 350 kelvin.
01:30
When k2 equals to 6 .9 into 10 to the power minus 4 per second, temperature t2 is equal to 400 kelvin.
01:54
Suppose ea indicates activation energy for this reaction.
02:10
From arrhenius equation, we know that a length k2 by k1 is equal to ea divided by gas constant r into t2 minus t1 divided by t1 into t2.
02:41
Now substitute the value of k1, k2, r, t1, t2 in this expression we get ln 6 .9 into 10 -res to the power minus 4 divide by 9 .3 into 10 -3 power minus 6.
03:02
Both have same unit.
03:04
Therefore we did not need to write it is equal to pa divide by.
03:14
Value of r is 8 .31 jule per mole per kelvin into t2 is equal to 400 kelvin and t1 is equal to 350 kelvin.
03:33
Divide by 400 kelvin into 350 kelvin.
03:45
By doing cross multiplication we get e .a equals to 8 .31 into 400 into 350 into ln, 2 ,300 divide by 31, whole divide by 50.
04:21
And here, remaining unit is joule per mole...