The reaction of 1 -chlorooctane with CH3 CO2^- to give octyl acetate is greatly accelerated by a

step 1 So we have the following reaction. We have one chloral octane, which is going to react with our

The reaction of 1 -chlorooctane with CH3 CO2^- to give octyl...

Key Concepts

SN2 Reaction Mechanism

The SN2 reaction mechanism is a one-step process in which a nucleophile attacks the electrophilic carbon from the opposite side of the leaving group, leading to simultaneous bond formation and bond breaking. This mechanism is characterized by a rate that depends on both the substrate and the nucleophile and typically proceeds with inversion of configuration at the reaction center.

Leaving Group Ability

The rate of nucleophilic substitution reactions is influenced by the quality of the leaving group. A good leaving group can stabilize the negative charge after departure. In this context, iodide is a better leaving group than chloride due to its larger size, higher polarizability, and the resulting weaker carbon-iodine bond, which makes the substitution reaction more favorable.

Halide Exchange (Finkelstein Reaction)

The Finkelstein reaction involves the exchange of one halide for another, typically replacing a poorer leaving group (chloride) with a superior one (iodide) by simple treatment with an iodide salt. Converting 1-chlorooctane into 1-iodooctane enhances the electrophilicity of the alkyl halide, thereby accelerating the subsequent nucleophilic attack by CH3CO2– to form octyl acetate.

Transcript

00:01 So we have the following reaction.

00:02 We have one chloral octane, which is going to react with our acetate.

00:07 And so we want to try to understand that why this is a relatively slow reaction, when we compare it to our one chloral octane reacting with acetate ion in the presence of an iodide ion.

00:20 So here this kind of requires us to look at our initial reaction here.

00:24 So we have our primary alkaliide, which is chloride.

00:28 It's a pretty decent leaving group, but compared to, say, iodide, we would say it's going to be a relatively poor leaving group.

00:36 And then we also have our acetate ion, which is a relatively weak nucleophile.

00:42 So on our own, we can conclude that, yeah, we're going to get a slow s &2 reaction.

00:53 And now we're going to look at the secondary reaction in which we have added iodide ion.

00:57 And we see it here.

00:59 Now we have a pretty weak nuclear file.

01:00 We have our acetate ion competing with a pretty strong nuclear file, which is our iodide.

01:05 So now our iodide is actually going to come in here.

01:11 So our iodide is actually going to come in here.

01:14 And it's going to act as a nucleophile, and it's going to perform backside attack.

01:18 And it's going to help our chloride leave.

01:20 And what we end up getting, let me erase this here, we end up getting our one iota octane now.

01:31 So it's going to look like this...

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