The reaction of 1,3 -butadiene with HBr is shown below. At $40^{\circ} \mathrm{C}$ the major product is the 1 . 4-addition product; however, at $-80^{\circ} \mathrm{C}$ the major product is the 1,2 -addition product.
Why are two products formed?
(a) The carbocation intermediate allows delocalisation of the second double bond.
(b) There are two double bonds present.
(c) The fact that the carbocation is planar allows attack from both sides of the plane.
(d) There are 2 moles of $\mathrm{HBr}$.