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The reaction of calcium hydride, $\mathrm{CaH}_{2},$ with water can be characterized as a Lewis acid-base reaction: $\mathrm{CaH}_{2}(s)+2 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{Ca}(\mathrm{OH})_{2}(a q)+2 \mathrm{H}_{2}(g)$ Identify the Lewis acid and the Lewis base among the reactants. The reaction is also an oxidation-reduction reaction. Identify the oxidizing agent, the reducing agent, and the changes in oxidation number that occur in the reaction.
in the above reaction the calcium hydroxide, $\mathrm{Ca}(\mathrm{OH})_{2}$ is a Lewis acid-base complex, in which $\mathrm{Ca}^{2+}$ is a Lewis acid and $\mathrm{OH}^{-}$ is a Lewis base.
Chemistry 101
Chapter 18
Representative Metals, Metalloids, and Nonmetals
Nonmetals Chemistry
University of Central Florida
Drexel University
Brown University
Lectures
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into this question where we identify the reducing and oxidizing agents in the Lewis and acid faces of this reaction, we first have to take each of the reactor of some products and break them up into there component ions as relevant. So Calculon hype hydride is laid up of calcium two plus and two each, minus hydride water. Um, for the sake of this problem, we're gonna say breaks up into hydra and I on in the high trucks that I am similarly, this is killed plus again hydroxide and each to is gonna be simply against a has each to. Actually, we'll just call it a JJ so that we can see we call it mutual age. We can see how the oxidation state change. It is clear that the calcium does not change oxidation states was essentially gonna stay dissolve in a solution. So for the purposes of this question, we can't ignore it. Similarly, for the hydroxide, you're essentially spectator I'll and what is left is are huh essentially the heist which shows that we had the hydride which started out in a minus one oxidation state. And it's gonna change into a you're oscillations seem So this hydride goes from minus 1 to 0. And the hydrogen I own from the water goes from positive one zero. You see here. So what we have here is the high Dr which loses an electron that is oxidation. While the hygiene ran through, the water is reduced because it gains in a lodger. Wants to go from plus 1 to 0 oxidation state. Okay, so what we've seen is that the species that undergoes oxidation is the Calkins hydride. So that means that this reducing agent, the substance that it's oxidized, is reducing. Agent in the substance that is reduced is the oxidizing agent who will fill in used to go here. Calcium. I drive out of here. What about the Louis based Louis acid? Remember that Lewis faces donate electrons. So what we have here is hydride and positive. Hydra and I on making each to. And what we have is this hydra donating this pair of electrons two, uh, hydrate and i'll So the substance that back of the Louis base, Yes. The hard drive in the Lewis acid, the 100 miles
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