Problem

Account for the increase in reaction rate brought…

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Problem 76 Hard Difficulty

The reaction of ${CO}$ with ${Cl}_{2}$ gives phosgene $({COCl}_{2}),$ a nerve gas that was used in World War I. Use the mechanism shown here to complete the following exercises: $\\$
${Cl}_{2}(g) \rightleftharpoons 2 {Cl}(g)$ (fast, ${k}_{1}$ represents the forward rate constant, $k_{-1}$ the reverse rate constant) $\\$
${CO}(g)+{Cl}(g) \rightarrow {COCl}(g)$ (slow, $k_{2}$ the rate constant)$\\$
${COCl}(g)+{Cl}(g) \longrightarrow {COCl}_{2}(g)$ (fast, $k_{3}$ the rate constant)$\\$
(a) Write the overall reaction.
(b) Identify all intermediates.
(c) Write the rate law for each elementary reaction.
(d) Write the overall rate law expression.

Answer

$\begin{aligned} \text { Overall rate } \operatorname{law} &=k_{2}[\operatorname{CO}]\left(\frac{k_{1}}{k_{-1}}\right)^{1 / 2}\left[\mathrm{Cl}_{2}\right]^{1 / 2} \\ &=k_{2}\left(\frac{k_{1}}{k_{-1}}\right)^{1 / 2}[\mathrm{CO}]\left[\mathrm{Cl}_{2}\right]^{1 / 2} \end{aligned}$

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Sharieleen A.

October 27, 2020

Rikhil M., thanks this was super helpful.

Damien W.

October 28, 2020

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Video Transcript

everyone says Ricky. And today we're working on problems. 76. This is a multi step problem. So we're gonna just go step by step. First, we're gonna discover right down the overall reaction. So we start with C L too makes to see l unearned carbon monoxide, plus C l makes C o C. L. Um Then we have CEO Seo plus C l makes CEO Seo, too. Um, Then we can cancel out some of our repeats to me. Make two seals here, but we use them there. We make a c o C. L Here, use it here. So we get that. The overall reaction is carbon monoxide is corinne is equal to a CEO seal, too. All right, so now we want Thio identify all the intermediates. Um, well, we already crossed out our intermediates. They are. We have two korans and I won coc elf. It's one, uh, coc. L um next we need to right down B rate law for each elementary reaction, and then right down the overall reaction. So we have first, um, So it was just maple. These one too. Three. So let's go to one. Um, we have K one seal to is equal to a case of the negative one of C l two. Um, we have step two is rate is equal to K two oven oxide times quarried step three rate is equal to K three. CEO Seo I'm seal and then for part, Devi will calculate the overall rate of reaction. And so we have to use thes slowest step, um, which is the second step. And so you get that be rate. Is he hold too. Que tu sio c l. But because see, a carbon monoxide and chlorine or intermittent gets, they shouldn't be in the final Great wall. So we have to rearrange, um, in solved for, uh, chlorine. So we arrange our first step sulphur quarry we get Barney is equal to came one over. Kate's a night of one, um, times for you suppose squared. And then we also want to solve, huh? Right now, we can plug in for Corinne to get the overall so we get that rate is equal to que tu times the square root of cave one over. Cates the negative warm, actually. Interesting. This they could have won times, frustration, carbon oxide, times square root of the situation. So I hope this video was helpful and I'll see you in the next one

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