Problem 95 Hard Difficulty

The reaction of $\mathrm{WCl}_{6}$ with Al at $\sim 400^{\circ} \mathrm{C}$ gives black crystals of a compound containing only tungsten and
chlorine. A sample of this compound, when reduced with hydrogen, gives 0.2232 $\mathrm{g}$ of tungsten metal and hydrogen
chloride, which is absorbed in water. Titration of the hydrochloric acid thus produced requires 46.2 $\mathrm{mL}$ of 0.1051 $\mathrm{M}$
$\mathrm{NaOH}$ to reach the end point. What is the empirical formula of the black tungsten chloride?

Answer

$\mathrm{WCl}_{4}$

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Chemistry 101

Chemistry

Chapter 4

Stoichiometry of Chemical Reactions

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Video Transcript

this question describes ah, reaction that essentially takes, uh, tungsten hex ical rider W C L six, and converts it over several steps to tungsten and HCL. It tells us that one of the intermediates along this path there's a compound that contains only tungsten and chlorine. But it doesn't tell us how doesn't tell us how much of each Adam there is. So I've written in Exeter. Why? Just to note some number of each of those atoms in this compound. And it tells us that, um, if this reaction is producing 0.2 to 32 grams of tungsten here, that also tells us that this acid can be neutralized with 46.2 mills 0.0. I'm sort of a point 1051 molar solution of any Ohh. So what? This information, we can figure out what the empirical formula is of this compound. Let's begin with the acid. It tells us that this could be neutralized. With 46.2 mills, I write that leaders 0.0 for 62 leaders of any ohh. That tells us the concentration is 0.1 051 Well, where 0.1051 mole of any a wage per leader of any O. H one leader, and we can convert between moles of any Ohh and bowls of HCL. It's a pretty common neutralization reaction. There's only one hydroxide ion per day, which molecule and only one proton pretty cr molecule. So it's 1 to 1. One more of any wage can neutralize one more of h c e o great, but we're not concerned with the number of most Dixie at work more concerned with the number of bowls of chlorine because that'll tell us how many clones were here. So we'll convert this one more time that saying that one more HCL contains one more of chlorine atoms. It's pretty straightforward. We should be able to cancel here. Leader, sodium hydroxide, mole sitting hydroxide, moles, hcl He was with moles of Corinne. If he did the math, you would get 0.0 zero for eat five moles and Corinne is that so much chlorine? There is in this final pre actives, so the next part would be this figure out how many moles of tungsten we had produced. It tells the a 0.22 read, too grams of tungsten. We can look up the Moler. Massive tungsten one tungsten is 183 Wentz, eat for grams of tungsten. He's cancel. Tend to you solve that. You would find that their 0.0 zero 121 malls. Tungsten. Great. So now the number of bowls of tungsten and we know the number of bowls of chlorine to find the molecular formula. I'm sorry, The empirical formula. We're going to divide each of those numbers. We divide the number most of tungsten by the number of moles, uh, chlorine and see what the ratio is between them. And if you do that, you would see that your answer is very close. 2.25 And you would recognize the 0.25 is the same as one over four sentence. To say that one mole of tungsten for every four moles of Cory answered and the empirical formula would be that ratio. No, I did Pierre Performers E f. It's getting equal. One more tungsten for formals of coin. So tungsten tetrachloride, This will be the empirical formula

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