00:01
All right, so we have the following reactions here, and we are told that these reactions are unlucky to occur.
00:06
So we want to go ahead and figure out what is wrong with each one of these and go ahead and predict the actual product.
00:12
So for our first reaction here, we have looks like we have a tube baromobutane, which is being reacted with the potassium terputoxide to form what it looks like as substituted product.
00:24
And we know that this is not going to occur.
00:28
So we would say we're not going to get this product because we know that when, whenever we react in alkohalide with a big bulky base like potassium turpid toxide, we're actually going to get an elimination reaction that favors the less substituted product.
00:42
So we would say the hoffman product due to steric hindrance.
00:47
And so what is going to actually happen is we are going to get the following reaction.
00:56
So i'm going to abbreviate potassium turpidotoxide as tbuok.
01:04
And then we're going to have an elimination reaction, right? so we're going to have the terminal hydrogen here, which is going to favor our hoffman product.
01:14
So these electrons are coming to come and deprotonate that hydrogen, and the electrons of the hydrogen are going to get pushed towards there and form a new pie bond.
01:22
And now our bromide's going to leave, so it's going to be an et2 elimination reaction.
01:29
And this is going to form our product, our hoffman product.
01:41
All right, so we would say that the hoffman is favored here, due to, due to our big bulky base.
01:50
And now we're given reaction b here, which we have a fluorosyclohexane, which is reacted with the sodium hydroxide to give us what looks like the substituted product.
01:58
Normally we would think, ok, sodium hydroxide's a very strong nucleophile.
02:02
And since fluoride is an alkaliate, it must be a good leaving group, although that is not really the case.
02:08
And we also have sodium hydroxide as a strong base.
02:10
So what is going to actually end up happening is an elimination reaction.
02:14
And we're going to get the following mechanism, right? so we're going to have, let's go ahead and draw our fluorosyclohexane here.
02:27
So we're going to end up deprotonating at one of the beta hydrogens.
02:31
It doesn't really matter which, because whether it's this one or this one, we're going to form the same product...