00:01
All right, we have a reduced row echelon formula for this matrix.
00:05
Remember when i set it up, my last column is always my answers, and my previous column referred to how many variables i have.
00:13
I've got four variables there because i've got four columns before.
00:17
Now, if this doesn't have a unique solution, we would have to write out the equations for each of them.
00:23
So it looks like x, y, and z are all dependent on w here.
00:28
So here we have 1x and 1 w still, equal to a negative 2.
00:36
Second row, we've got 1y, 2 w which is equal to 2.
00:42
And here we've got 1 z minus a w, which is equal to 0.
00:49
And we know that this is consistent.
00:51
It's dependent, though, just because our last row is a true statement...