Question
The reflecting surfaces of two intersecting flat mirrors are at an angle $\theta\left(0^{\circ} < \theta < 90^{\circ}\right)$ as shown in Figure $\mathrm{P} 25.18$. For a light ray that strikes the horizontal mirror, show that the emerging ray will intersect the incident ray at an angle $\beta=180^{\circ}-2 \theta$.
Step 1
The sum of the angles in a triangle is 180 degrees. Therefore, we have: \[2\alpha + 2\gamma + \beta = 180^{\circ}\] Rearranging this equation, we get: \[\beta = 180^{\circ} - 2(\alpha + \gamma) \tag{1}\] Show more…
Show all steps
Your feedback will help us improve your experience
Mohamed Raafat Mohamed and 84 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
The reflecting surfaces of two intersecting flat mirrors are at an angle $\theta\left(0^{\circ}<\theta<90^{\circ}\right),$ as shown in Figure $\mathrm{P} 35.27$ For a light ray that strikes the horizontal mirror, show that the emerging ray will intersect the incident ray at an angle $\beta=180^{\circ}-2 \theta .$
The reflecting surfaces of two intersecting flat mirrors are at an angle of $\theta\left(0^{\circ}<\theta<90^{\circ}\right),$ as shown in the figure below. A light ray strikes the horizontal mirror. Use the law of reflection to show that the emerging ray will intersect the incident ray at an angle of $\phi=180^{\circ}-2 \theta$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD