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The reflecting surfaces of two mirrors form a vertex with an angle of $110^{\circ} .$ If a ray of light strikes mirror 1 with an angle of incidence of $45^{\circ}$ , find the angle of reflection of the ray when it leaves

mirror 2 .

Thus, the angle of reflection of the ray when it leaves mirror 2 is $\left[65^{0}\right]$

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questions. Three says the reflecting surfaces of two mirrors former Vertex of 110 degrees will draw premieres, and there is 110 degrees between them. And it says, if a ray strikes a mere one will not mere one be down here with an angle of incidence of 45 degrees. Find the angle of reflection of the ray when it leaves Mir two. So I'm gonna have my normal wine here, and then our incident Ray will come in at 45 degrees, which means, of course, it leaves at 45 degrees and it's going to strike that mirror and then it'll bounce off. Of that mere at the same angle is the angle of incidence will be the angle of reflection. So we need to find what that angle of incidence is. Of course, we know this is a 45 degree angle here, and we know that this is a 45 degree angle here because that's a 45 degree angle and the whole thing is perpendicular. We also know that this is 100 and 10 degrees, so if I have 110 degrees plus 45 degrees plus X is equal to 180 because there's 180 degrees in the triangle. And so if we find that angle will also know our angle of incidents in our angle of reflection. So 110 plus 45 is 155 plus X equals 1 80 minus 1 55 from both sides. And so axes, of course, 25 degrees. Now that's not quite the answer to the question is is fine the angle of reflection of the ray when it leaves Mir two's. The angle of reflection is, of course, over here, but we just found this English is 25 degrees, so that's 65 degrees for right here. And so that's our angle of incidence, which is also our angle of reflection 65 degrees.