00:01
Okay, so no resistance can be equal to roll l over a, which is equal to row l over 4 piar square, since the area of the sphere is equal to 4 pi r square.
00:09
So if we take differentiation on each side, eventually we have dr is equal to row dr over 4pyr square.
00:17
And d lowercase r here is the thickness of the sphere.
00:21
So now we can use the integral to determine the expression for the resistance.
00:26
We should have r is equal to integral dr, which is equal to integral, row d r over four pi r square range from a to b and then if we do some range here we have r is equal to row over four pi times integral one over r square d r and the range from a and b and then we can take the antiderative of one over r square which is equal to negative one over r and the range is still the same which is from a to b so now we can plug in the value a and b to the one over r so eventually we have r r is equal to row over 4 pi times b minus a over ab.
01:12
So for question b, we know current density can be equal to current divided by area.
01:16
And current can be equal to v over r.
01:18
V is the potential, and the r is the resistance.
01:22
So if you do some arrangement here, we have j is equal to v over a.
01:26
So in this case, you were saying that the potential difference is a bab...