Question
The resistance of a galvanometer coil is 25.0 $\Omega$, and the current required for full-scale deflection is 500 $\mu$A. (a) Show in a diagram how to convert the galvanometer to an ammeter reading 20.0 mA full scale, and compute the shunt resistance. (b) Show how to convert the galvanometer to a voltmeter reading 500 mV full scale, and compute the series resistance.
Step 1
0 \, \Omega$ and the current required for full-scale deflection is $I_G = 500 \, \mu A = 500 \times 10^{-6} \, A$. We want to convert the galvanometer to an ammeter reading $I = 20.0 \, mA = 20 \times 10^{-3} \, A$ full scale. Show more…
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The resistance of a galvanometer coil is $25.0 \Omega,$ and the current required for full-scale defiection is 500$\mu A$ . (a) Show in a diagram how to convert the galvanometer to an ammeter reading 20.0 $\mathrm{mA}$ full scale, and compute the shumt resistance. (b) Show how to convert the galvanometer to a voltmeter reading 500 $\mathrm{mV}$
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The resistance of a galvanometer coil is 30.0 ̤, and the current required for full-scale deflection is 0.500 mA. Part A Show in a diagram how to convert the galvanometer to an ammeter reading 25.0 mA full scale. add a shunt resistor in parallel with the galvanometer coil add a resistor in series with the galvanometer coil Part B Complete previous part(s) Part C Show how to convert the galvanometer to a voltmeter reading 500 mV full scale. add a shunt resistor in parallel with the galvanometer coil add a resistor in series with the galvanometer coil Part D Complete previous part(s)
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