Question
The resistivity of resistive wire is $\rho=(\mathrm{AR} / \mathrm{L})$ where $L=$ length of wire $A=$ Area of wire and $R$ is resistance of wire find dimension formula of $\rho$(a) $\mathrm{M}^{1} \mathrm{~L}^{3} \mathrm{~T}^{-3} \mathrm{~A}^{-2}$(b) $\mathrm{M}^{1} \mathrm{~L}^{2} \mathrm{~T}^{-3} \mathrm{~A}^{-2}$(c) $\mathrm{M}^{2} \mathrm{~L}^{3} \mathrm{~T}^{1} \mathrm{~A}^{2}$(d) $\mathrm{M}^{2} \mathrm{~L}^{3} \mathrm{~T}^{-3} \mathrm{~A}^{-2}$
Step 1
We know that the dimensions of area (A) is $L^2$, the dimensions of resistance (R) is $M L^2 T^{-3} A^{-2}$, and the dimensions of length (L) is $L$. Show more…
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The dimensional formula of resistivity of a conductor is a. $\left[M L^{2} T^{-2} A^{-2}\right]$ b. $\left[M L^{3} T^{-3} A^{-2}\right]$ c. $\left[M L^{-2} T^{-2} A^{2}\right]$ d. $\left[M L^{2} T^{-2} A^{-3}\right]$
The equation for the resistivity of a conductor is: R = ̑L / A where: R is the resistance in ohms (̑) ̑ is the resistivity of the material in ohm-meters (̑ ∙ m) L is the length of the conductor in meters (m) A is the cross-sectional area of the conductor in square meters (m²) Let's use your data to find the resistivity of this conductor. The diameter of this conductor is 2.1 mm. What is the cross-sectional area in meters squared? 1.39 x 10⁻⁵ m² 3.46 x 10⁻⁶ m² 3.46 x 10⁻⁴ m² 1.39 x 10⁻³ m² 6.6 x 10⁻³ m²
The force per unit length of wire $\mathrm{B}$, exerted by wire $\mathrm{A}$ is given by $\mathrm{F}=\frac{\mathrm{kl}_{1} \mathrm{I}_{2}}{\mathrm{r}} .$ Where $\mathrm{r}$ is the separation between the parallel wires carrying currents $\mathrm{I}_{1}$ and $\mathrm{I}_{2} .$ The dimensional formula of $\mathrm{k}$ is (a) $\mathrm{ML}^{2} \mathrm{~T}^{-2} \mathrm{I}^{2}$ (b) $\mathrm{MLT}^{-2} \mathrm{I}^{-2}$ (c) $\mathrm{ML}^{2} \mathrm{TI}^{2}$ (d) $\mathrm{M}^{2} \mathrm{~L}^{2} \mathrm{~T}^{2} \mathrm{I}^{-2}$
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