00:02
Hi, in this given problem, the circuit which was used in the previous problem was having the uppermost branch having two resistors in series, having the value of 2 .0 -oam each, r1 and r2.
00:25
Then there is a middle branch having a resistance r4 is equal to 2.
00:33
0 .0 ome and the bottom most branch that was having a resistance of r3 2 .0 om in the previous previous problem problem number 14 there was a single resistance but now here in this problem we are joining one more resistance let it be r5 and that is also having a value of 2 .0 om and that is join in series with r3 and having the same battery having the same potential 12 volt.
01:09
Now in the first part of the problem we have to discuss what will happen to the currents passing through all these resistors.
01:20
So i -1 in the upper most branch where i -1 and i -2 will be same.
01:24
This is i -4 passing through the middle branch and here this will be i -3 passing through the bottom -most branch.
01:32
So in the first part of the problem on joining one more resistance which we are considering as r5 having a value of 2 .0 oam in series with r3 the current in this branch which is i3 will decrease using om's law current depends inversely on the resistance as resistance has been increased so the current will decrease but that in other branches means i1 and i4 will remain same using oms law where current is given by i is equal to v by r and potential remains the same in parallel so as there is no change in the potential so the potential across the uppermost branch and the middle branch will remain same hence the current passing through them will remain same but the current i3 will decrease so we conclude the net current coming out of the battery will also decrease this is the answer for the first part of the problem now in the second part of the problem we have to find the current passing through various resistors now the net resistance of the uppermost branch which is having two resistors in series r1 and r2 so that will be r s1 is equal to r1 plus r2 or we can say this is 2 .0 plus 2 .0 ome...