00:01
Question number 34 is asking us what the aperture of a radio telescope would have to be to give it a resolution comparable to that of the human high.
00:10
Now, our formula for angular resolution is theta is equal to 2 .06 times 10 to the 5th power times lamb, lambda over d arc seconds.
00:40
Theta is our angular resolution.
00:45
Lambda is the wavelength at which we observe, and d is the diameter of our aperture.
00:52
Now for this problem, we're given a few different variables.
00:57
We're actually given theta right off the bat.
01:00
Theta is equal to 1 .5.
01:06
Arc minutes, that's the resolution of the human eye.
01:14
And we're also given lambda.
01:18
That's the 21 centimeters, which is the wavelength at which the radio telescope observes.
01:28
So in this question, we're not asked to find theta, we're actually asked to find d.
01:35
Now, notice that our resolution is given in arc minutes.
01:39
We we want that in order for our units to be consistent, we want that in arc seconds.
01:45
So all we need to do is multiply 1 .5 times their 60 arc seconds within one arc minute.
02:02
So we just do a bit of unit conversion.
02:07
And we get theta is equal to 90 arc seconds.
02:20
Same thing with lambda.
02:22
We want lambda to be measured in meters, usually.
02:26
That's the best unit form for our wavelength.
02:32
So there are 100 centimeters in a meter...