the-rms-current-in-an-ac-circuit-with-a-resistance-of-150omega-is-015-a-what-are-a-the-average-and-b

Question

The rms current in an ac circuit with a resistance of 150$\Omega$ is
0.15 A. What are (a) the average and (b) the maximum power con-
sumed by this circuit?

João Gabriel Alencar Caribé · Accepted Answer

this question says that they are a mask you&#x27;re into running through a secret is off 0.15 and peers and such circle. It has 150 homes off resistance. In the first item off the question, we have to calculate what is the average power consumers by such circuit. So So we have to use the following relation. I believe he is equals to our times. I r M s squared and now we have to do now is plaguing the given values in this equation to get our first answer. So 150 times zero point 15 squared and these easy goes to three point 3 75 What off consumer power. In the second item, we have to calculate the maximum power consumers by that circuit. So the maximum power it&#x27;s too close to and times the maximum current squared. And now we have to complete what is the maximum current? So remember that we have this relation between the Ari mask. You&#x27;re it onda maximum current. So the ari masking her it is the question the maximum clearance divided by the square root of two. Then the maximum could rent is it close to They are a mass current times the square root of two. So the maximum power consumers by the circuit is equal to are times two things I R and s squared and leaders equals two, 150 times two times 0.15 square. Which easy course, too. Six 0.75. What?

Salamat Ali · Answer

but a off the even problem. Um, we know from this relation that re maximum physical Thio We are a mess times they&#x27;re swearing off it too. From here we can write, but a that is a re max will be equal to our mess. Given is 1 20 times where route off too. This gives us remax off 1 70 year olds. I want to be, um Wi Max weekend right is from all those law are times I&#x27;m ex and from here I Max will be cool too. You called to 1 70 17 to do right by resistance, which is 1.5 times. Don&#x27;t our three year old homes. Um, excuse us there. I&#x27;m excellent. 0.11 in Pierre, look. See? Oh, we can find the I are in this by dividing I Max, I&#x27;m expe I screwed over to this. Is there a 0.11 in Pierre, If I buy skirt off to this gives us Ah, the current off our famous eight times dental baller minus to appear body we confined. Average power is equal to, um the We are in this square. Our miss were divided by the resistance so substituting values 1 20 Um, we have got a power. The re arm s off 1 20 So 1 20 square. Divided by resistance. 1.5 times. Don&#x27;t power three. This uses the power off 9.6 wars.

Ze-Han Lee · Answer

All right. So Ah, this problem. We have our see serious circuit. And we know the are in the reactions of the camp Asta and that Ah, I am Dr. So we also know the average electric power consumed the to resist is 60 warts. So, uh, gonna find other power factor off the circuit, the power factor simply there was I here. The power factor is, uh, course and five equal to our over Z. Okay. Always given in the sea According to the definition, it&#x27;s r squared. Plus client C minus. Kyle split, and they have a spare route. So this is he And we have also in this formula, we already know that are in the Chrissie and the cry l So we can just a plot these numbers into this formula and find out the finest. The final result is, uh, your 0.85. So this is Apollo Factor and for part B. So what is the arms? Betty of the village. Ah, So we already know the power off the resister, which is the P people Thio I r M s. I am Mrs The current is our EMS current in the circuit split The Times are So this is the power consuming the interest in the register, uh, equal to 60 waltz we already know are So we&#x27;re gonna find out i r m s able thio 0.44 72 peers and then we can figure out the total Ah, the arms very off the voltage Armas able to the current R. M s times in penance. So here is the expression for the practice. So just plug in the numbers and you&#x27;ll see that the better it is 1 61 What&#x27;s okay?

Luis Mendoza · Answer

so pretty scrolling were considering on our Lissy circuit on the circuit House resist or we tend homes. Resistance Capacitance, off 12 0.0 Total Ferrets conductors off syrup ones who are 17. Hendry&#x27;s on all the story elements are collectively Siri&#x27;s do on a senior writer with 100 55 bolts on first winning to find what is the frequency. Because, I said the current said his maximum on the grand halls of silicate. Well, I was gonna be this maximum when the generator has the frequency that if the circuits restaurant pregnancy, I always need to find that rested and frequency, which is the invited standard equation. One over to buy the courtroom healthy. Well, any numbers between a resonant frequency of 352 hertz don&#x27;t remember. By definition of the resonant frequency, it means that the capacity reactions and inducted reactors cancel each other out so the impotence is equal to the resistance, so C equals R. Then the current in the circuit is simply even by the voltage of the generator, divided by parties resistance, which is keeps us. Our Karenna off 15.5 appears

Ryan Hood · Answer

to get the power factor of the circuit. We&#x27;re going to need the impudence of circuit to get the impudence of circuit. We&#x27;re going to use this formula here. Impedance is equal to the square of our squared, plus the difference in react, Ince&#x27;s square and we know what everything on the right hand side is. It&#x27;s all given the problem so we can plug it all in and sell for the impedance to get 361 homes. And so now we can use the formal for the power factor, which is the resistance over the impedance. The resistance is given in the problem and the impedance we just found. And so the power factors, Eagle says. You&#x27;re appointing through one and that&#x27;s answer party for Part B. We&#x27;re going to use the formula that the power is equal to the R. M s current school here. Tens of resistance. Let&#x27;s solve this for the Army&#x27;s current. I get this very of power over their resistance, and so now we complying with the power isn&#x27;t going in with the resistance is to get the army&#x27;s current, and it&#x27;s you&#x27;re a 0.447 camp ears and so now that we know that we can figure out what the Army&#x27;s voltages by using this formula, we figured out what the impedance was here, and we just figured out what the Army&#x27;s current is here. And so I complied all of that and to get 161 bolts, which is the Armas voltage, and that completes the problem.

Mohit Khurana · Answer

welcome to the program but thirty one point two for this is a pretty one are rendered in current So in this question were given a circuit and all the components are connected in Siri&#x27;s So we have the circuit we have Is his source connected? This is the systems are contestants I&#x27;ll say this is inducted capacitance in the system wear given that the source world which Aramis is a castrated hold the frequency of the icy sources one twenty hard and we have the impudence to visit because to one hundred five and their assistants were least seventy five. So we need to find out that the average power is delivered by the toe, the circuit by the source. So let&#x27;s do this one. So we have First, we will need to use these formulas here given here. So we have I reminisce, Which is it close to via Aramis or we Jet And we know the values that and we know they went to the Vietnamese. So this comes to be point seven six two MPs. Now we need to find out the course, fi, so we have course five, which is because two are over them. So this&#x27;s seventy five over one zero five. So this comes out to be point seven one four now finding out the average power. So we&#x27;re back. Back in the main calculation, which is we are a message is eighty times I armies, which is point seven six two. Just not backed by cause five with his point seven one four. So this comes out to be forty three point five worked. So this is a power delivered to the circuit by the S s sold. And that&#x27;s your answer for this question. Thank you for watching every deal.

Problem

A $3.33-\mathrm{k} \Omega$ resistor is connected …

Problem 4 Easy Difficulty

The rms current in an ac circuit with a resistance of 150$\Omega$ is
0.15 A. What are (a) the average and (b) the maximum power con-
sumed by this circuit?

Answer

a) $3.375 \mathrm{w}$
b) $6.75 \mathrm{~W}$

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James S. Walker

Physics

Marshall S.

Farnaz M.

Zachary M.

Meghan M.

Electric Charge

The Electric Force

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a) $3.375 \mathrm{w}$b) $6.75 \mathrm{~W}$

Physics

Marshall S.

Farnaz M.

Zachary M.

Meghan M.

Electric Charge

The Electric Force

James S. WalkerPhysics

Marshall S.

Farnaz M.

Zachary M.

Meghan M.

a) $3.375 \mathrm{w}$
b) $6.75 \mathrm{~W}$

James S. Walker

Physics