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The rms voltage across a $0.010-\mu \mathrm{F}$ capacitor is 2.8 $\mathrm{V}$ at a fre-quency of 75 $\mathrm{Hz}$ . What are (a) the rms and (b) the maximum cur-rent through the capacitor?

a) $1.32 \times 10^{-5} \mathrm{A}$b) $1.87 \times 10^{-5} \mathrm{A}$

Physics 102 Electricity and Magnetism

Chapter 24

Alternating-Current Circuits

Current, Resistance, and Electromotive Force

Direct-Current Circuits

Electromagnetic Induction

Alternating Current

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to complete the fiery mass current that is flowing from that circuit. We only have to use the following relation. I r m s is equals two to quiet times the frequency times the capacitance times the ROMs Voltage, then plaguing the given data We got that I are a mess is equals two to pie times 75 times 0.0 10 times 10 to the minus six Don't forgot that micro there times two 0.8 and leave things approximately because too 13 0.2 times 10 to the minus six, which can be read him US 13.2 micro m peers in the second item, we have to complete the maximum current that is flowing for that circuit. So remembering the relation between the maximum current on the Aramis current I r m s is equals two i max divided by the square root of two. We get that the maximum current is it close to the armory mass current times the square root of two plugging in the value that have just calculated for the r. A masquerade we get to that. The maximum current is equals two 13.2 times stand to the minus six times this choir tough, too, and this is approximately close to 18.7 times 10 to the minor six, which can be read in US 18.7 Micro and peers.

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