We can do this by taking moments about points A and C.
For rod CD, taking moments about point A, we get:
\[F_{CD} \times 10 - 5 \times 7.6 - 2 \times 4 = 0\]
Solving for \(F_{CD}\), we get \(F_{CD} = 6.67 \, kN\).
For rod AB, taking moments about point C, we
Show more…