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The root mean square speed of $H_{2}$ molecules at 25 °C is about 1.6 km/s. What is the root mean square speed of a $N_{2}$ molecule at 25 °C?

0.43 $\mathrm{km} / \mathrm{s}$

01:25

Aadit S.

Chemistry 101

Chapter 9

Gases

Carleton College

Rice University

Drexel University

Brown University

Lectures

05:03

In physics, a gas is one o…

04:46

In physics, thermodynamics…

02:47

Determine the root-mean-sq…

02:38

Oxygen molecules have an a…

02:21

What is the ratio of the r…

05:07

If the speed of an oxygen …

04:23

At $20^{\circ} \mathrm{C}$…

02:25

The average temperature at…

04:12

$\bullet$$\bullet$ At what…

06:16

Calculate the root mean sq…

01:44

At a certain temperature t…

04:28

$\bullet$ Oxygen $\left(\m…

03:36

Calculate the rms speed fo…

03:04

At what temperature is the…

02:07

The rms speed of an oxygen…

03:06

01:29

What is meant by the root-…

The root-mean-square speed…

00:54

06:10

The average speed of molec…

02:05

What is the ratio of the a…

02:08

The average speed of a nit…

so continuing on with the content surrounding the root mean square velocity. So the root, mean square velocity of a particle is defined as the square root of the average of these squares of the velocities with any number of particles. So we'll look at this in every real life example. So we've got into an H two to consider. So you root mean square of end to bye bye, you root mean square H two is equal to the 2 g the mall that's the molecular mass of H two by 28 g per mole minus one. I'm like most event too together from the periodic table. This equals once we stop any valley for H two, so body for eight shares, 1.6 key kilometers per second. So then are root, mean square speech velocity for and to not 0.43 kilometers per second. So the root mean square speed event to will be not 0.43 kilometers per second

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